An element crystallizes in fcc lattice. If the edge length of the unit cell is 408.6 pm and the density is `10.5 g cm^(-3)`. Calculate the atomic mass of the element.

Explanation

Data: `d=10.5 g cm^(-3)`
`a= 408.6 xx 10^(-12) m = 408.6 xx 10^(-10) cm = 4.086 xx 10^(-8)` cm
For the fcc lattice =(Z)=4
Formula: `d=(Z xx M)/(a^(3) xx N_(A)), M=(d xx a^(3) xx N_(A))/Z`
`M=(10.5 xx (4.086 xx 10^(-8))^(3) xx 6.022 xx 10^(23))/4`
M=107.8