Niobiumcrystallizs in body centered strucure. If density is 8.55 g `cm^(-3)`. Calculate the edge lengthof the unit cell (Atomic mass = 93 u).

Explanation

Data Z=2, M= 93 M,`d= 8.55 g cm^(-3), N_(A) = 6.022 xx 10^(23)`
Formula: `a^(3) = (ZM)/(d xx N_(A))`
`a^(3) = (2.93)/(8.55 xx 6.022 xx 10^(23))`
`a^(3) = 36.12 xx 1^(-24) cm^(3)`
`a=(36.12 xx 10^(-24))^(1//3)`
`a=(36.12)^(1//3) xx 10^(-3) =1/3 log 36.12 xx 10^(-3) = 1/3 xx 1,557 xx 10^(-8)`
a= Antilog `0.5192 xx 10^(-8)`
a=330.6 pm.