Calculate the EMF of the cell for the reaction.
`Mg_((s))+2Ag_((aq))^+ Mg_((aq))^++2Ag(s)`
Given: `E^@ Mg^(2+)//Mg=-2.37 V`
`E^@ Ag^(+)//Ag=0.08V`
`[Mg^(2+)]=0.001M,[Ag^+]=0.0001M`
`log 10^5=5`

Explanation

Data:
`E_((Ag^(+))/(Ag))^(0)=0.80V, E_((Mg^(2+))/(Mg))=-2.37V`
`E_("cell")^(0)=overset(oplus_(0))(E)-overset((-)_(0))(E)=E_(Ag)^(0)-E_(2Ag)^(0)=0.80-(-2.37)=3.17V`
`[Mg^(2+)]=0.001M [Ag^(+)]=0.0001M`
Cell reaction:
`Mg^(2+)(aq)+2Ag^(+)(aq) to Mg^(2+)(aq)+2Ag(s)`
n=2
Formula:
`E_("cell")=E_("cell")^(0) -(0.0591)/(n)log""([Mg^(2+)])/([Ag^(+)]^(2))`
Substitution:
`E_("cell")=3.17 -(0.0591)/(2)log""([0.001])/([0.001]^(2))`
`E_("cell")=3.022V`