Represent the cell in which the following reaction takes place
`Mg(s)+2Ag^(+)(0.001M) to Mg^(2+)(0.130)+2Ag(s)`
Calculate `E_("cell")" if "E_("cell")^(0)=3.17V`.

Explanation

Represent of the cell
`Mg//Mg^(2+)(0.130M)||Ag^(+)(0.01M)//Ag`
Cell reaction `Mg+2Ag^(+) to Mg^(2+)+2Ag`
FORMULA: `E_("cell")=E_("cell")^(0)-(0.059)/(n)log""([Mg^(2+)])/([Ag^(+)]^(2)]`
Substitution `E_("cell")=3.17-(0.059)/(2)log"" ([0.130])/([0.0001)]^(2))`
=2.96V