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Calculate the equilibrium constant for t...

Calculate the equilibrium constant for the reaction
`Cu(s)+2Ag+(aq)rarrCu^(+2)(aq)+2Ag(s),E_("cell")^(@)=0.46V`.

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Date `E^(0)=0.46V, n=2, F=96500"C mol"^(-1)`
Formula: `E_("cell")^(0)=(2.303RT)/(nF)log K_(C).`
At 298 K 0.46 `=(0.059)/(2)log K_(C)`.
`log K_(C)=(0.46 xx 2)/(0.059)`
`log K_(C)=15.6`
`K_(C)=3.92 xx 10^(5)`.
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