If `t a n x+tan(x+pi/3)+tan(x+(2pi)/3)=3,` then prove that `(3tanx-t a n^3x)/(1-3t a n^2x)=1` .

Explanation

To solve the problem, we start with the equation given:

\[ \tan x + \tan\left(x + \frac{\pi}{3}\right) + \tan\left(x + \frac{2\pi}{3}\right) = 3 \]

### Step 1: Use the tangent addition formula
We will use the tangent addition formula:
...