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If t a nbeta=(nsinalphacosalpha)/(1-nsin...

If `t a nbeta=(nsinalphacosalpha)/(1-nsin^2alpha)` , show that `tan(alpha-beta)=(1-n)t a nalphadot`

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Given,
`=>tanβ=(nsinαcosα​)/(1−nsin^2α)`
dividing by `cos^2alpha`
`=>(ntanα​)/(sec^2α−ntan^2α)`
`=>(ntanα​)/(1+tan^2α−ntan^2α)`
`=>(ntanα​)/(1+(1−n)tan2α)`
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