Find the following integrals:(i) `int(dx)/(x^2-16)` (ii) `int(dx)/(sqrt(2x-x^2))`

Explanation

Let's solve the integrals step by step.

### Part (i): Find \( \int \frac{dx}{x^2 - 16} \)

1. **Identify the form of the integral**:
The integral can be recognized as a standard form:
\[
\int \frac{dx}{x^2 - a^2} = \frac{1}{2a} \log \left| \frac{x - a}{x + a} \right| + C
...