If `sin A=3/5 ,0 < A < pi/2 and cosB=(-12)/(13),0 < B < (3pi)/2,` find the following `sin(A-B)` (ii) `"cos"(A+B)` (iii) `tan(A-B)`

Explanation

To solve the problem, we will find the values of \( \sin(A - B) \), \( \cos(A + B) \), and \( \tan(A - B) \) step by step.

### Given:
- \( \sin A = \frac{3}{5} \) and \( 0 < A < \frac{\pi}{2} \)
- \( \cos B = -\frac{12}{13} \) and \( 0 < B < \frac{3\pi}{2} \)

### Step 1: Find \( \cos A \)
Using the Pythagorean identity \( \sin^2 A + \cos^2 A = 1 \):
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