Given that: `(1+cosalpha)(1+cosbeta)(1+cosgamma)=(1-cosalpha)(1-cosbeta)(1-cosgamma)dot` Show that one of the values of each member of this equality is `sinalphasinbetasingammadot`

Explanation

To show that \((1 + \cos \alpha)(1 + \cos \beta)(1 + \cos \gamma) = (1 - \cos \alpha)(1 - \cos \beta)(1 - \cos \gamma)\) implies that one of the values of each member of this equality is \(\sin \alpha \sin \beta \sin \gamma\), we can follow these steps:

### Step 1: Start with the given equation
We have:
\[ (1 + \cos \alpha)(1 + \cos \beta)(1 + \cos \gamma) = (1 - \cos \alpha)(1 - \cos \beta)(1 - \cos \gamma) \]

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