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HC-=CH underset(("excess"))overset(HoCl)...

`HC-=CH underset(("excess"))overset(HoCl) (to)A`
`CH_(3)-C-=CH underset(("excess"))overset(HOCl) (to) B`
A nad B are respectively :

A

`Cl_(2)CH-CHO "and" CH_(3)-C Cl_(2) -CHO`

B

`Cl_(2)CH-CHO "and" CH_(3)underset(O)underset(||)C-CHCl_(2)`

C

`Cl_(2)CH-COOH "and" CH_(3)C Cl_(2)COOH`

D

`Cl_(2)CHOOH "and"CH_(3)underset(O)underset(||)C-CHCl_(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
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