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A body falls from rest freely under grav...

A body falls from rest freely under gravity with an acceleration of `9.8 m//s^(2)`. Neglecting air resistance, the distance travelled by the body during the third second of its motion will be:

A

14.7 m

B

24.5 m

C

19.6 m

D

29.4 m

Text Solution

Verified by Experts

The correct Answer is:
B

`s = u + (1)/(2) g (2t - 1)`
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