For a particle moving along a straight line, its velocity 'v' and displacement 's' are related as `v^(2) = cs`, here c is a constant. If the displacement of the particle at `t = 0` is zero, its velocity after 2 sec is:

Options

A. `(c)/(2) s^(0)`
B. `cs^(0)`
C. `(c)/(2) s^(-1)`
D. `cs^(-1)`

Answer

B

Explanation

`v = sqrtc sqrts`
`(ds)/(dt) = sqrtc sqrts`
`int_(0)^(s) s^(-1//2) ds = sqrtc int_(0)^(2) dt`
`2sqrts = sqrtc xx 2`
`sqrts = sqrtc`