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A body is thrown vetically upward at t =...

A body is thrown vetically upward at `t = 0`. It is at a height 80 m at two instant `t_(1)` and `t_(2)`, then `t_(1) t_(2)` is: (Take `g = 10 m//s^(2)`)

A

30

B

24

C

16

D

12

Text Solution

Verified by Experts

The correct Answer is:
C
`t_(1) t_(2) = (2H)/(g)`
`t_(1) t_(2) = (2 xx 80)/(10) = 16`
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