A car 2m long and 3m wide is moving at `10m//s` when a bullet hits it in a direction making an angle of `tan^(-1)(3//4)` with the car as seen from the ground. The bullet enters one edge of the car at the corner and passes out at diagonally opposite corner. Neglecting gravity, the time for the bullet to cross the car is

Options

A. 0.20 s
B. 0.15 s
C. 0.10 s
D. 0.50 s

Answer

A

Explanation

Relative velocity along x-axis is `(v_(b) cos 37^(@) - 10)`
Distance travelled by bullet along x-axis is
`(v_(b) cos 37^(@) - 10) t = 2`
Distance travelled by bullet along y-axis is
`(v_(b) sin 37^(@)) t = 3`
Solving equations (i) and (ii), we get `t = 0.20 s`