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A projectile is lauched with a velocity ...

A projectile is lauched with a velocity u at right angles to the along, which in inclined at an angle 1 with the horizontal. Derive an expression for the distance R to the point of impact.

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The correct Answer is:
`R=(4u^(2))/(g)tan theta "sec" theta`

`R=(1)/(2)gsin theta(T)^(2)`
`T=(2u)/(g cos theta)`
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