A body has maximum range `R_(1)` when projected up the inclined plane. The same body when projected down, the inclined plane. It has maximum range `R_(2)`. Find its maximum horizontal range. Assume the equal speed of projection in each case and the body is projected onto the gretest slope.

Options

A. `R=(2R_(1)R_(2))/(R_(1)-R_(2))`
B. `R=(2R_(1)R_(2))/(R_(1)+R_(2)`
C. `R=(R_(1)R_(2))/(R_(1)-R_(2))`
D. `R=(4R_(1)R_(2))/(R_(1)+R_(2))`

Answer

c

Explanation

For upward projecton, `R_("max")=(V_(0)^(2))/(g(1-sinbeta))=R_(1)` .............(i)
For downward projection `R_("min")=(v_(0)^(2))/(g(1+sin beta))=R_(2)` ..........(ii)