A trolley A has a simple pendulum suspended from a frame fixed to its deck A block B is in contact on its vertical side. The trolley is on horizontal rails and accelerates towards the right, such that the block is just

prevented from falling. If the value of coefficient of friction between A and B is 0.5 find the value of the inclination of the pendulum to the vertical.

Answer

`theta=tan^(-1) (2)=63.4^(@)`

Explanation

F.B.D of block `B rarr`
`N=ma`
`muma = mg`
`a=g/mu=(10xx10)/5=20m//sec^(2)`
`"Now "tan theta=a/g=20/10=2`
`theta=tan^(-1)2`