A van accelerates uniformly down an inclined hill going from reast to `30m//s` in `6s`. During the acceleration , a toy of mass `m=0.1kg` hangs by a light string from the van's ceiling . The acceleration is such that string remains perpendicular to the ceiling. `(` Take `g=10m//s^(2))`

The tension n the string is

Answer

`(a) 30.7^(@)`
`(b) 0.843 N`

Explanation

`(a) v=at`
`a=30/6=5m//sec^(2)`
as `tan theta=a/g`
`:. tan theta = 5/10=1/2`
`theta=30.7^(@)`

(b)