A body of mass M rests on a horizontal plane having coefficient of friction `mu` . At `t=0` a horizontal force `vec(F)` is applied that varies with time `vec(F)(t)=vec(F)_(0)` t where `vec(F)_(0)` is a constant vector. The time instant `t_(0)` at which motion starts and distance moved in t second will be:

Options

A. `(Mg)/(muF_(0))and F_(0)/M(t-t_(0))^(2)`
B. `(muMg)/F_(0) and 1/6F_(0)/M(t-t_(0))^(3)`
C. `(muF_(0))/(Mg)and F_(0)/M(t-t_(0))^(2)`
D. `F_(0)/(Mg) and F_(0)/(2Mg)(t-t_(0))^(2)`

Answer

B

Explanation

`M((dv)/(dt))=F_(0)t`