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In fig tension in the string that connec...

In fig tension in the string that connects the masses A and B is `T_(1)` and that in the string connecting B and C is `T_(2)` then `T_(1)/T_(2)` is:

A

2

B

`0.5`

C

4

D

`0.25`

Text Solution

Verified by Experts

The correct Answer is:
A
`a=((m_(1)-m_(2))/(m_(1)+m_(2)))g=((2m-m)/(2m+m))g=g/3`
`T_(1)=2m(g-a)=2m(g-g/3)=2/3mg`
`:. T_(1)/T_(2)=2`
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