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In fig mass m is lifted up by attaching ...

In fig mass m is lifted up by attaching a mass 2m to the other end of the string while in fig
(b) m is lifted by pulling the other end of the string with a constant force `F=2mg` then:

A

acceleration of m in the two situations is same and non - zero

B

acceleration of m in situation
(a) is more than that of in situation(b)

C

acceleration of m in situation
(a) is less than that of in situation
(b)

D

acceleration of m in the two situations is same and equals to zero

Text Solution

Verified by Experts

The correct Answer is:
C
In situation (a)
`2mg-T=2ma`
`T-mg=ma`
In situation (b)
`T-mg=ma`
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