In fig a sphere of mass 2 kg is suspended from the ceiling of a car which is initially at rest. Tension in the string in this situation is `T_(1)` The car now moves to the right with a uniform acceleration and the tension in the string is now `T_(2)` then: (Take `g=10m//s^(2)`)

Options

A. `T_(1)=T_(2)=20N`
B. `T_(1)=20N, T_(2) gt20N`
C. `T_(1)=20N, T_(2) lt20N`
D. `T_(1) lt20N,T_(2)=20N`

Answer

B

Explanation

`T_(1)=mg=2xx10=20N`
`T_(2)=sqrt((mg)^(2)+(ma)^(2))=msqrt(g^(2)+a^(2))`
Thus, `T_(2) gt T_(1)`