A balloon of gross weight W newton descends with an acceleration `fm//s^(2)` The weight that must be thrown out in order to give the balloon an equal upward acceleration will be:

Options

A. `(Wf)/g`
B. `(2Wf)/g`
C. `(2Wf)/(g+f)`
D. `(W(g+f))/f`

Answer

C

Explanation

`W-T=W/g "(f)"`....(i)
`T-W'=(W')/g f` ....(ii)
`W'=("final weight")`