A mass of 10 kg is suspended from a spring balance, it is pulled aside by a horizontal string so that it makes an angle `60^(@)` with the vertical. The new reading of the balance is:

Options

A. `10sqrt(3)` kg wt
B. `20 sqrt(3)` kg wt
C. 20 kg wt
D. 10 kg wt

Answer

C

Explanation

`T=(Mg)/(cos theta)=100xx2=200N`
`"reading"=T/g=20 kg wt.`