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Two masses m(1) and m(2) are accelerated...

Two masses `m_(1)` and `m_(2)` are accelerated uniformly on a frictionless surface as shown in figure given below. The ratio of the tensions `T_(1)/T_(2)` is:

A

`m_(1)/m_(2)`

B

`m_(2)/m_(1)`

C

`((m_(1)+m_(2)))/m_(2)`

D

`m_(1)/((m_(1)+m_(2)))`

Text Solution

Verified by Experts

The correct Answer is:
D
`T_(1)=m_(1)a and T_(2)=(m_(1)+m_(2))a`
`:.(T_(1))/T_(2)=m_(1)/((m_(1)+m_(2)))`
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