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A particle moves in the x-y plane under ...

A particle moves in the x-y plane under is influence of a force such that its linear momentum is `vec(P)(t)=A[hat(i)cos (kt)-hat(j)sin (kt)]`, where A and k are constants Angle between the force and the momentum is:

A

`0^(@)`

B

`30^(@)`

C

`45^(@)`

D

`90^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
`vec(F)=(dvec(P))/(dt)`
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