A particle is moving in a circular path. The acceleration and moment of the particle at a certain moment are `a=(4 hat(i)+3hat(j))m//s^(2) and p=(8 hat(i)-6hat(j))"kg-m/s"`. The motion of the particle is

Options

A. uniform circular motion
B. accelerated circular motion
C. decelerated circular motion
D. we cannot say anything with `vec(a) and vec(p)` only

Answer

B

Explanation

`vec(a)=4hati+3hatj`
`vec(P)=8hat(i)-6hat(j)`
`a_(c)=V^(2)/R=4`
`a_(t)=((dV)/(dt))=3`