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The figure shows the position-time (x-t) graph of one-dimensional motion of a body of mass 0.4kg. The magnitude of each impulse is

A

`0.2 Ns`

B

`0.4 Ns`

C

`0.8 Ns`

D

`1.6 Ns`

Text Solution

Verified by Experts

The correct Answer is:
C

Velocity with which the body strikes the ground is
`v_(1)=(0-2)/(4-2)=-1m//s=1m//s("downward")`
Velocity with which body rise after rebounding is
`v_(2)=(2-0)/(6-4)=1m//s("upward")`
Impulse = Change in momentum
`=0.4[1-(-1)]=0.8 Ns`
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