A space- craft of mass 100 kg breaks into two, when its velocity is `10^(4)ms^(-1)` After the break a mass of 10 kg of the space craft is left stationary the velocity of the remaining part is:

Options

A. `10^(3)ms^(-1)`
B. `11.11 xx 10^(3)ms^(-1)`
C. `11.11xx10^(2)ms^(-1)`
D. `10^(4)ms^(-1)`

Answer

B

Explanation

Using the law of conservation of linear momentum
`MV=m_(1)v_(1)+m_(2)v_(2)`
`100xx10^(4)=10xx0+90xxv_(2)`
`v_(2)=100/90xx10^(4)=11.11xx10^(3)ms^(-1)`