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Under the action of force P, the constan...

Under the action of force P, the constant acceleration of block B is `3 ms^(-2)` to the right. At the instant when the velocity of B is `2 ms^(-1)` to the right, determine the velocity of B relative to A, the acceleration of B relative to A and the absolute velocity of point C of the cable.

A

2

B

1

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
B

`-3TV_(B)+4TV_(A)=0, V_(A)=3/4V_(B)=3/2`
`(V_(B)+V_(C))/2=V_(A),V_(C)=2V_(A)-V_(B),V_(C)=3-2=1`
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