A string of negligible mass going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given by

Options

A. `sqrt(2)Mg`
B. `sqrt(2) mg`
C. `(sqrt((M+m)^(2)+m^(2)))g`
D. `(sqrt((M+m)^(2)+M^(2)))g`

Answer

D

Explanation

Two forces act on the pulley, the force `T=mg` acts horizontally and the force `(M+m)g` acts vertically. The resultant force on the pulley is:
`=(sqrt((M+m)^(2)+M^(2)))g`