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In the situation given, all surfaces are...

In the situation given, all surfaces are frictionless. Pulley is ideal and string is light if `F=mg//2` the acceleration of the big block is `g//x` then x is:

Text Solution

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The correct Answer is:
4
First consider both the blocks as system force that we apply at one end of string is tension in the string
For system block `(A+B)(Mg)/2=2Ma a=g/4`
Thus, `a=g/(4hat(i))`

For system block A: `Mg-(Mg)/2=Ma_(r)`
`vec(a)_(r)=g/(2hat(j))`
Thus, `vec(a)_(A)=g/(4hat(i))+g/(2hat(j))`
`vec(a)_(3)=g/(4hat(j))`
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