Calculate the number of `kJ` of heat necessary to raise the temperature of `60.0 g` of aluminium from `35^(@)C` to `55^(@)C`. Molar heat capacity of `Al` is `24 J g m^(-1)`.

Answer

1.067 kJ

Explanation

From the expression of heat (q),
`q=m.c.DeltaT`
Wher,
c= molar heat capacity
m= mass of substance
`DeltaT` = change in temperature
Substituting the values in the expression of q:
`q=((60)/(27)"mol")(24 J "mol"^(-1)K^(-1))(20 K)`
q=1066.7J
q=1.07 kJ