Two resistors of resistances `R_(1)=100 pm 3` ohm and `R_(2)=200 pm 4` ohm are connected (a) in series, (b) in parallel. Find the equivalent resistance of the (a) series combination, (b) parallel combination. Use for (a) the relation `R=R_(1)+R_(2)` and for (b) `1/(R')=1/R_(1)+1/R_(2)` and `(Delta R')/R'^(2)=(Delta R_(1))/R_(1)^(2)+(Delta R_(2))/R_(2)^(2)`

Explanation

To solve the problem of finding the equivalent resistance of two resistors \( R_1 = 100 \pm 3 \, \Omega \) and \( R_2 = 200 \pm 4 \, \Omega \) connected in series and parallel, we will follow these steps:

### Part (a): Series Combination

1. **Calculate the Equivalent Resistance:**
The formula for the equivalent resistance \( R \) in series is given by:
\[
R = R_1 + R_2
...