A substance weight 5.74 g occupies a volume of `1.2cm^3.` Caluclate its density with due regard to significant digits.
Text Solution
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There are 3 significant figures in the measured mass whereas there are only 2 significant figures in the measured volume. Hence the density should be expressed to only 2 significant figures. Density `=5.74/1.2 g cm^(-3)` `=4.8 g cm^(-3)`
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