The escape speed of a projectile on the earth's surface is 11.2 `km` `s^(-1)`. A body is projected out with thrice this speed. What is the speed of the body far away from the earth? Ignore the presence of the sun and other planets.

Explanation

To solve the problem, we will use the principle of conservation of energy. The total mechanical energy of the body at the surface of the Earth will be equal to the total mechanical energy of the body when it is far away from the Earth.

### Step-by-Step Solution:

1. **Identify the escape speed**: The escape speed from the Earth's surface is given as \( V_E = 11.2 \, \text{km/s} \).

2. **Calculate the initial speed of the body**: The body is projected with thrice the escape speed. Therefore, the initial speed \( V_0 \) of the body is:
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