Estimate the fraction of molecular volume to the actual volume occupied by oxygen gas at STP. Take the diameter of an oxygen molecule to be `3 Å`.

Explanation

Diameter of an oxygen molecule ,d=3 Å
Raidus `=(d)/(2)=(3)/(2)`
`= 1.5 Å = 1.5 × 10_(–8)` cm
Actual volume occupied by 1 mole of oxygen gas at STP = `22400 cm^3`
` V=(4)/(3) pir^(3).N` Molecular volume of oxygen gas ,
Where ,N is Avogadro's number `=6.023xx10^23` molecules /mole
`therefor V =(4)/(3)xx3.14xx(1.5xx10^-8)^3xx6.023xx10^23=8.51 cm^3`
Ratio of the molecular volume to the actual volume of oxygen` =(8.51)/(22400)`
`=3.8xx10^-4`