A 12 pF capacitor is connected to a 50 V battery. How much electrostatic energy is stored in the capacitor ?

Explanation

Capacitor of the capacitance , C=12 pF =`12xx10^(-12)F`
potential difference, V=50 V
Electrostatic energy stored in the capacitor is given by the relation,
`E=1/2 CV^(2)`
`=1/2 xx12 xx10^(-12) xx(50)^(2)`
`=1.5xx10^(-8) J`
Therefore, the electrostatic energy stored in the capacitor is `1.5xx10^(-8)J`.