If the axes are shifted to the point `(1,-2)` without rotation, what do the following equations become? `2x^2+y^2-4x+4y=0` `y^2-4x+4y+8=0`

Explanation

First equation

`2x^2+y^2-4x+4y=0`

`2(x-1)^2+(y+2)^2-4(x-1)+4(y+2)=0`

`2(x^2+1-2x)+y^2+4+4y-4x+4+4y+8=0`

`2x^2+2-2x+y^2+4-4y-4x+4+4y+8=0`

`2x^2+y^2-6x+8y+18=0`

`y^2-4x+4y+8=0`

`y^2+8y-4x+24=0`.