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In sulphur estimation, 0.157 g of an org...

In sulphur estimation, 0.157 g of an organic compound gave 0.4813 g of barium sulphate. What is the percentage of sulphur in the compound?

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Molecular mass of `BaSO_(4)` = 137+32+64
=233g
233 g `BaSO_(4)` contains 32 g sulphur
0.4813 g `BaSO_(4)` contains `(32xx0.4813)/233` g sulphur
Percentage of sulphur = `(32xx0.4813xx100)/(233xx0.157)`
=42.10%
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