Two sitar strings A and B playing the note 'Ga' are slightly out of tune and produce beats of frequency 6 Hz. The tension in the string A is slightly reduced and the beat frequency is found to reduce to 3 Hz. If the original frequency of A is 324 Hz, what is the frequency of B?

Explanation

Frequency of string A, `f_(A)` = 324 Hz
Frequency of string `B = f_(B)`
Beat’s frequency, n = 6 Hz
Beat's frequency is given as :
`n=|f_(A)+-f_(B)|`
`6=324 +-f_(B)`
`f_(n)=330 Hz` or 318 Hz
Frequency decreases with a decrease in the tension in a string. This is because frequency is directly proportional to the square root of tension. It is given as:
`V prop sqrt(T)`
Hence, the beat frequency cannot be 330 Hz
`therefore f_(B)=318 Hz`