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Using the standard electrode potentials...

Using the standard electrode potentials given in Table, predict if the reaction between the following is feasible`:`
`a. Fe^(3+)(aq)` and `I^(c-)(aq)`
`b.` `Ag^(o+)(aq)` and `Cu(s)`
`c.` `Fe^(3+)(aq)` and `Br^(c-)(aq)`
`d.` `Ag(s)` and `Fe^(3+)(aq)`
`e. ``Br_(2)(aq)` and `Fe^(2+)(aq)`.

Text Solution

Verified by Experts

(a) The possible reaction between `Fe_((aq))^(3+) + I_((aq))^(-)` is given by ,
`2Fe_((aq))^(3+) + 2I_((aq))^(-) to 2 Fe_((aq))^(2+) + I_(2 (s))`

`E^(@)` for the overall reaction is positive . Thus , the reaction between `Fe_((aq))^(3+)` and `I_((aq))^(-)` is feasible .
(b) The possible reaction between `Ag_((aq))^(+) + Cu_((s))` is given by ,
`2Ag_((aq))^(+) + Cu_((s)) to 2 Ag_((s)) + Cu_((aq))^(2+)`

`E^(@)` positive for the overall reaction is positive. Hence, the reaction between`Ag_((aq) ` and `Cu_((s)` is feasible .
(c) The possible reaction between `Fe_((aq))^(3+)` and `Cu_((s))` is given by ,
`2Fe_((aq))^(3+) + Cu_((s)) to 2Fe_((s))^(3+) + Cu_((aq))^(2+)`

`E^(@)` positive for the overall reaction is positive . Hence , the reaction between `Fe_((aq))^(3+)` and `Cu_((s))` is feasible .
(d) The possible reaction between `Ag_((s))` and `Fe_((aq))^(3+)` is given by ,
`Ag_((s)) + 2 Fe_((aq))^(3+) to Ag_((aq))^(+) + Fe_((aq))^(2+)`

Here `E^(@)` for the overall reaction is negative . Hence , the reaction between `Ag_((s))` and `Fe_((aq))^(3+)` is not feasible .
(e) The possible reaction between `Br_(2 (aq))` and `Fe_((aq))^(2+)` is given by ,
`Br_(2 (s)) + 2Fe_((aq))^(2+) to 2Br_((aq))^(-) + 2 Fe_((aq))^(3+)`

Here `E^(@)` for the overall reaction is positive . Hence , the reaction between `Br_(2 (aq))` and `Fe_((aq))^(2+)` is feasible .
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