Given standard electrode potentials
`K^(o+)|K=-2.93V, Ag^(o+)|Ag=0.80V`,
`Hg^(2+)|Hg=0.79V`
`Mg^(2+)|Mg=-2.37V,Cr^(3)|Cr=-0.74V`
Arrange these metals in their increasing order of reducing power.

Explanation

The lower the electrode potential , the stronger is the reducing agent . Therefore , the increasing order of the reducing power of the given metals is `Ag lt Hg lt Cr lt Mg lt K`.