In Rutherford's nuclear model of the atom, the nucleus (radius about `10^(-15)m`) is analogous to the sun about which the electron moves in orbit (radius about `10^(-10)m`) like the earth orbits around the sun. If the dimensions of the solar system had the same proportions as those of the atom, would the earth be closer to or further away form the sun than actually it is ? The radius of earth's orbit is about is `1.5xx10^(11)m`. The radius of the sun is taken as `7xx10^8m`.

Explanation

The ratio of the radius of electron’s orbit to the radius of
nucleus is `(10^(–10) m)/(10^(–15) m) = 10^(5)`, that is, the radius of the electron’s orbit is `10^(5)` times larger than the radius of nucleus. If the radius of the earth’s orbit around the sun were `10^(5)` times larger than the radius of the sun, the radius of the earth’s orbit would be `10^(5) × 7 × 10^(8)` m =`7 × 10^(13)` m. This is more than 100 times greater than the actual orbital radius of earth. Thus, the earth would be much farther away
from the sun. It implies that an atom contains a much greater fraction of empty space than our solar system does.