Home
Class 12
PHYSICS
The linear mass density of a ladder of l...

The linear mass density of a ladder of length `l` increases uniformly from one end `A` to the other end `B`,
(a) Form an expression for linear mass density as function of distance `x` from end `A` where linear mass density `lambda_(0)`. The density at one end being twice that of the other end.
(b) find the position of the centre of mass from end `A`.

Text Solution

Verified by Experts

The correct Answer is:
`5/9`L
Promotional Banner

Topper's Solved these Questions

  • CENTRE OF MASS

    MOTION|Exercise Exercise - 4 Level-I|18 Videos

  • CENTRE OF MASS

    MOTION|Exercise Exercise - 4 Level-II|20 Videos

  • CENTRE OF MASS

    MOTION|Exercise Exercise - 3 Level-I|34 Videos

  • Capacitance

    MOTION|Exercise EXERCISE -4 LEVEL II|19 Videos

  • CIRCULAR MOTION

    MOTION|Exercise EXERCISE - 4|16 Videos

Similar Questions

Explore conceptually related problems

The mass of an uniform ladder of length l increases uniformly from one end A to the other end B, find the position of the centre of mass from end A.

The linear mass density lambda of a rod AB is given by lambda =aplha+betaxkg/m taking O as origin. Find the location of the centre of mass from the end A?

If the linear density of a rod of length L varies as lambda = A+Bx , find the position of its centre of mass .

Find coordinates of mass center of a non-uniform rod of length L whose linear mass density lambda varies as lambda=a+bx, where x is the distance from the lighter end.

The density of a thin rod of length l varies with the distance x from one end as rho=rho_0(x^2)/(l^2) . Find the position of centre of mass of rod.

The linear density of a thin rod of length 1m lies as lambda = (1+2x) , where x is the distance from its one end. Find the distance of its center of mass from this end.

Find centre of mass of given rod of linear mass density lambda=(a+b(x/l)^2) , x is distance from one of its end. Length of the rod is l .

The linear mass density of a rod of length 2L varies with distance (x) from center as lambda=lambda_(0)(1+(x)/(L)) .The distance of COM from center is nL.Then n is

MOTION-CENTRE OF MASS-Exercise - 3 Level-II
  1. Mass is non - uniformly distributed on the circumference of a ring of ...

    Text Solution

    |

  2. The linear mass density of a ladder of length l increases uniformly fr...

    Text Solution

    |

  3. The linear mass density of a ladder of length l increases uniformly fr...

    Text Solution

    |

  4. A 24-kg projectile is fired at an angle of 53^(@) above the horizontal...

    Text Solution

    |

  5. A 24-kg projectile is fired at an angle of 53^(@) above the horizontal...

    Text Solution

    |

  6. The simple pendulum A of mass m(A) and length l is suspended from the ...

    Text Solution

    |

  7. Two masses A and B connected with an inextensible string of length l l...

    Text Solution

    |

  8. Mass m(1) hits m(2) with inelastic impact (e=0) while slliding horizon...

    Text Solution

    |

  9. Mass m(1) hits m(2) with inelastic impact (e=0) while slliding horizon...

    Text Solution

    |

  10. Mass m(1) hits m(2) with inelastic impact (e=0) while slliding horizon...

    Text Solution

    |

  11. Mass m(1) hits m(2) with inelastic impact (e=0) while slliding horizon...

    Text Solution

    |

  12. A particle A of mass 2 kg lies on the edge of a table of height 1m. It...

    Text Solution

    |

  13. As shown in the figure a body of mass m moving vertically with speed 3...

    Text Solution

    |

  14. A particle is projected from point O on level ground towards a smooth ...

    Text Solution

    |

  15. A particle is projected from point O on level ground towards a smooth ...

    Text Solution

    |

  16. A particle is projected from point O on level ground towards a smooth ...

    Text Solution

    |