The simple pendulum A of mass `m_(A)` and length l is suspended from the trolley B of mass `m_(B)`. If the system is released from rest at `theta = 0`, determine the velocity `v_(B)` of the trolley and tension in the string when `theta = 90°`. Friction is negligible.

Answer

`V_(B)=(m_(A))/(m_(B))sqrt((2gl)/(1+m_(A)//m_(B)));T=3m_(A)g+(2m_(A)^(2)g)/(m_(B))`