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Mass m(1) hits m(2) with inelastic impac...

Mass `m_(1)` hits `m_(2)` with inelastic impact (e=0) while slliding horizontally with velocity v along the common line of centres of three equal mass as shoun in fugure `-4.155.` Initially, masses `m_(2)` and `m_(3)` are stationary and the spring is unstressed. Find:

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The correct Answer is:
`x=sqrt(m//6k)v`
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MOTION-CENTRE OF MASS-Exercise - 3 Level-II
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