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A simple pendulum simple harmonic motion...

A simple pendulum simple harmonic motion about `x = 0` with an amplitude a and time period `T` speed of the pendulum at `x = a//2` will be

A

`(pia sqrt(3))/(T)`

B

`(pia sqrt(3))/(2T)`

C

`(pi a)/(T)`

D

`(3 pi^(3)a)/(T)`

Text Solution

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The correct Answer is:
A
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