Home
Class 12
PHYSICS
The equation of motion of a particle sta...

The equation of motion of a particle started at `t=0` is given by `x=5sin(20t+pi//3)` where x is in centimeter and t in second. When does particle
(a) first come to rest
(b) first have zero acceleration
(c) first have maximum speed?

Text Solution

Verified by Experts

(a) `(pi)/(120) `sec , (b) `(pi)/(30) ` sec (c ) `(pi)/(30)` sec.
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARONIC MOTION

    MOTION|Exercise EXERCISE -3 (Leve-I) ( SECTION - B ) ( Time per iod and angular frequency in SHM )|4 Videos
  • SIMPLE HARONIC MOTION

    MOTION|Exercise EXERCISE -3 (Leve-I) ( SECTION - C ) ( Two block system )|2 Videos
  • SIMPLE HARONIC MOTION

    MOTION|Exercise EXERCISE -2 (Leve-I I) ( SECTION - H ) ( Combination of two or more SHM )|4 Videos
  • SIMPLE HARMONIC MOTION

    MOTION|Exercise EXERCISE -3 Section - B Previous Year Problems | JEE MAIN|23 Videos
  • SOUND WAVES

    MOTION|Exercise Exercise - 3 (Section - B)|14 Videos